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%   An exact certificate for all 16 Boolean functions on {-1,1}^2
%   at noise correlation rho = 1/2, including equality cases,
%   explicit strict gaps, and the corresponding Courtade--Kumar
%   corollary.
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% The all-dimensional assertions of Family 119 remain external
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\title{\textbf{Oai119-A}\\
An Exact Finite Certificate for Hellinger Contraction\\
on the Two-Dimensional Discrete Cube\\[3pt]
\large Equality, strict gaps, the information corollary,\\
and a seven-stage audit of Family 119}
\author{Ngo Cheung}
\date{14 October 2026}

\begin{document}
\maketitle

\begin{abstract}
We complete the finite-certificate task proposed for Family 119,
without assuming either of its all-dimensional contraction
claims. For the uniform cube \(\{-1,1\}^2\) and independent
symmetric noise of correlation \(1/2\), we give the complete
stochastic matrix, classify all sixteen Boolean functions, and
prove the Hellinger inequality by exact algebra. Equality holds
precisely for the four signed coordinates. Every other Boolean
function has Hellinger gap greater than \(27/1000\). For parity
the gap lies strictly between \(102/1000\) and \(103/1000\);
for the nonconstant biased orbit it lies strictly between
\(27/1000\) and \(28/1000\). All comparisons reduce to displayed
integer-square inequalities.

We prove the classical convexity argument that converts a
Hellinger certificate into a Courtade--Kumar certificate. It
yields, at the frozen instance, the sharp bound
\(1-h_2(1/4)\), the same equality cases, and a mutual-information
gap greater than \(1/50\) bit for every nonsigned-coordinate
function. The rest of the manuscript freezes the distinct
soft-information and Hellinger assertions, audits their
proof interfaces, and separates arithmetic certification,
sampling, implementation resources, and quantum recovery.
The general Family 119 proofs remain unverified here.
No quantum-channel, fidelity, gravitational, or spacetime
conclusion is claimed.
\end{abstract}

\tableofcontents

\section{Stage 0: objects, normalizations, and claim status}
\label{sec:freeze}

\subsection{The task completed here}

The single new target selected by the plan is an explicit finite
Hellinger certificate at one specified dimension and correlation.
Theorem~\ref{thm:finite} completes that target for
\[
n=2,\qquad \rho=\frac12.
\]
It covers \emph{every} Boolean function at this frozen instance,
not merely a named coordinate and one selected comparison.

The all-dimensional soft-information and Hellinger statements
are recorded separately below. They are not hypotheses of
Theorem~\ref{thm:finite}. Completing one finite instance does not
verify either general proof.

The finite calculation is elementary and is not represented as
a new resolution of the original conjectures. Its contribution
is a fully specified, reproducible certificate with explicit
gaps and a clearly bounded dependency structure.

\subsection{Uniform cube and symmetric product noise}

Let
\[
\Omega_n=\{-1,1\}^n,\qquad
\E u=2^{-n}\sum_{x\in\Omega_n}u(x).
\]
For \(-1\le\rho\le1\), define
\begin{equation}
K_\rho(x,y)
=
\prod_{i=1}^n\frac{1+\rho x_i y_i}{2},
\qquad
T_\rho u(y)=\sum_{x\in\Omega_n}K_\rho(y,x)u(x).
\label{eq:kernel}
\end{equation}
The matrix \(K_\rho\) is symmetric and stochastic. In
probabilistic terms, \(X\) is uniform and
\[
Y_i=X_iZ_i,\qquad
\Prob(Z_i=1)=\frac{1+\rho}{2},
\]
where the \(Z_i\) are mutually independent and independent of
\(X\). Both \(X\) and \(Y\) are uniform. Symmetry gives
\[
T_\rho u(Y)=\E[u(X)\mid Y].
\]
These are the standard cube-noise conventions
\cite{ODonnell,CourtadeKumar2014}.

A Boolean function takes values in \(\{-1,1\}\).
A soft summary takes values in \([-1,1]\).
A signed coordinate is \(f(x)=\sigma x_i\), with
\(\sigma\in\{-1,1\}\).

\subsection{Three different scalar functions}

To avoid the conflicting uses of \(H\) in the source
manuscripts, define
\begin{align}
\ell&=\ln2,\\
h(t)&=
-\frac{1+t}{2}\ln\frac{1+t}{2}
-\frac{1-t}{2}\ln\frac{1-t}{2},
&&-1\le t\le1,\\
\psi(t)&=\ell-h(t)
=
\frac{1+t}{2}\ln(1+t)
+\frac{1-t}{2}\ln(1-t),\\
H(t)&=\sqrt{1-t^2}.
\label{eq:profiles}
\end{align}
The convention is \(0\ln0=0\).
Thus \(h\) is sign entropy in nats, \(\psi\) is its deficit
from \(\ell\), and \(H\) is the Hellinger profile.
They are not interchangeable.

For a soft summary \(u\), put
\begin{equation}
\Isoft(u)=h(\E u)-\E h(u)
=\E\psi(u)-\psi(\E u).
\label{eq:softinfo}
\end{equation}
Binary entropy in bits is
\[
\hbin(p)=-p\log_2p-(1-p)\log_2(1-p).
\]
We write \(\Info_2(A;B)\) for classical mutual information in
bits and \(\Info(A;B)=\ell\,\Info_2(A;B)\) for the same
quantity in nats.

\begin{lemma}[The classical information identity]
\label{lem:infoidentity}
Given \(u:\Omega_n\to[-1,1]\), construct a sign \(U\) with
\[
\Prob(U=b\mid X=x)=\frac{1+b\,u(x)}2,
\qquad b\in\{-1,1\},
\]
using auxiliary randomness independent of the noise conditional
on \(X\). Then
\[
\Info(U;X)=\Isoft(u),
\qquad
\Info(U;Y)=\Isoft(T_\rho u).
\]
For Boolean \(f\), one may take \(U=f(X)\), and
\begin{equation}
\Info_2(f(X);Y)
=
\hbin\!\left(\frac{1+m}{2}\right)
-
\E\hbin\!\left(\frac{1+T_\rho f}{2}\right),
\qquad m=\E f.
\label{eq:MI}
\end{equation}
\end{lemma}

\begin{proof}
The conditional mean of \(U\) given \(X\) is \(u(X)\), so its
conditional entropy is \(\E h(u)\), while its mean is \(\E u\).
This proves the first identity. Conditional expectation and
the stated conditional independence give
\[
\E[U\mid Y]
=
\E[u(X)\mid Y]
=
T_\rho u(Y).
\]
The same entropy calculation proves the second identity.
For Boolean \(f\), \(U=f(X)\) has zero conditional entropy
given \(X\), and division by \(\ell\) gives \eqref{eq:MI}.
\end{proof}

No intermediate measurement, quantum observable, or decoding
operation occurs in this identity.

\subsection{The two general assertions being audited}

\begin{claimrecord}[119-01: soft contraction and Boolean refinement]
\label{rec:soft}
The manuscript \emph{Sharp binary-information contraction on the
discrete cube}, dated 24 September 2026, asserts
\begin{equation}
\Isoft(T_\rho u)
\le
\psi\!\left(|\rho|\,\psi^{-1}(\Isoft(u))\right)
\label{eq:external-soft}
\end{equation}
for every soft summary on every finite uniform cube.
The inverse is the increasing branch from \([0,\ell]\) to
\([0,1]\). Soft coordinates attain equality.

For Boolean \(f\) of mean \(m\), its
\texttt{main:ck} specializes this to
\begin{equation}
\Info(f(X);Y)
\le\psi(|\rho|r_m)\le\psi(|\rho|),
\qquad
r_m=\psi^{-1}(h(m)).
\label{eq:external-refined}
\end{equation}
The refined upper curve is strictly below the universal curve
when \(0<|m|<1\) and \(0<|\rho|\le1\).
Its separate \texttt{upgrade:production} asserts a stronger,
mean-dependent production bound
\cite{OpenAI119I}.
\end{claimrecord}

\begin{claimrecord}[119-02: arbitrary-bias Hellinger contraction]
\label{rec:hellinger}
The manuscript \emph{Hellinger contraction with arbitrary Boolean
output bias}, also dated 24 September 2026, asserts
\begin{equation}
H(m)-\E H(T_\rho f)\le1-H(\rho),
\qquad m=\E f,
\label{eq:external-H}
\end{equation}
for every Boolean \(f\), every dimension, and every correlation.
Signed coordinates attain equality. Its
\texttt{cor:ck} derives the ordinary Courtade--Kumar bound from
this assertion \cite{OpenAI119II,OpenAI119Implication}.
\end{claimrecord}

The Courtade--Kumar formulation in bits is
\begin{equation}
\Info_2(f(X);Y)\le1-\hbin(\varepsilon),
\qquad
\varepsilon=\frac{1-\rho}{2}.
\label{eq:CK}
\end{equation}
For \(\rho<0\), the same formula is valid because
\(\hbin(\varepsilon)=\hbin(1-\varepsilon)\).

\begin{remark}[Debugging the relation between the manuscripts]
The two papers concern the same noisy Boolean-summary problem,
but their displayed general assertions are different.
The soft-information theorem includes randomized summaries at
fixed initial information. The Hellinger theorem controls a
different functional and implies the ordinary Boolean
information bound. We do not assert that the two displayed
theorems are equivalent, nor that either general proof is a
premise of the other.

The implication from Hellinger to Courtade--Kumar predates
these manuscripts \cite{ABCJN}. Its elementary proof is
included in Section~\ref{sec:implication}.
\end{remark}

\subsection{Lean scope and the inspected target files}

The scope note \texttt{lean/docs/119.md} names 119-01 and
describes soft contraction, the Boolean refinement, and the
selected production inequality \cite{Lean119Scope}.
The inspected Comparator challenge files
\texttt{CourtadeKumar.lean} and
\texttt{SoftChannel204.lean} specify these targets. Their
respective principal theorem bodies,
\texttt{courtadeKumarAndAttainment} and
\texttt{fullMain}, contain \texttt{sorry}
\cite{Lean119CK,Lean119Soft}.

Thus the inspected target files are not completed proofs of
those theorem bodies. This is a statement about the inspected
files, not an exhaustive inspection of every possible solution
artifact. The Hellinger inequality of 119-02 is not separately
specified by these targets. No Lean execution or independent
formal verification is asserted here.

\section{Stage 1: the five proof interfaces}
\label{sec:audit}

The following audit supplies elementary identities and identifies
the nontrivial universal obligations. Recording an obligation
does not discharge it.

\subsection{Gate 1: scalar rate and effective amplitude}

\begin{lemma}[Scalar profile facts]
\label{lem:scalar}
The function \(\psi\) is even, continuous on \([-1,1]\),
strictly increasing on \([0,1]\), and strictly convex.
For \(|r|<1\),
\[
\psi'(r)=\atanh r,
\qquad
\psi''(r)=\frac1{1-r^2}.
\]
Furthermore,
\[
0\le\Isoft(u)\le h(\E u)\le\ell,
\]
and \(\Isoft(u)=0\) if and only if \(u\) is constant.

Define \(F:[0,\ell)\to[0,\infty)\) by
\begin{equation}
F(\psi(r))=r\atanh r,
\qquad 0\le r<1.
\label{eq:F}
\end{equation}
Then \(F(0)=0\), \(F'(0)=2\), \(F\) is convex, and
\(F(s)\ge2s\).
\end{lemma}

\begin{proof}
The derivatives follow by differentiation.
The range of \(\psi\) on \([0,1]\) is \([0,\ell]\).
Jensen's inequality proves nonnegativity of \(\Isoft\),
with equality precisely for constant \(u\), by strict convexity.
Its upper bound follows from \(h\ge0\).

For \(r>0\), put \(V=\atanh r\). The chain rule gives
\[
F'(\psi(r))
=
1+\frac{r}{(1-r^2)V},
\]
and
\[
F''(\psi(r))
=
\frac{(1+r^2)V-r}{(1-r^2)^2V^3}>0,
\]
because \(V\ge r\).
The expansion \(V=r+O(r^3)\) gives \(F'(0)=2\).
Convexity and the tangent at zero give \(F(s)\ge2s\).
\end{proof}

For a soft coordinate \(u(x)=a x_i\),
\[
\Isoft(u)=\psi(|a|),\qquad
T_\rho u=\rho a x_i,\qquad
\Isoft(T_\rho u)=\psi(|\rho a|).
\]
This checks the asserted equality example directly, without
proving the universal upper bound.

The scalar parameter
\(\psi^{-1}(\Isoft(u))\) is an effective coordinate amplitude.
It is not a channel capacity and does not construct an optimizer
over arbitrary summary tables.

\subsection{The mean-dependent production profile}

To state the production claim precisely, let
\[
S(s)=F(s)-2s\quad(0\le s<\ell),
\qquad S(s)=0\quad(s<0).
\]
For \(|m|<1\) and \(0\le I<h(m)\), define
\begin{equation}
\mathcal B_m(I)
=
2I+(1-m^2)
S\!\left(\ell-\frac{h(m)-I}{1-m^2}\right),
\qquad
\widehat{\mathcal B}_m(I)
=
\max\{\mathcal B_m(I),F(I)\}.
\label{eq:Bprofile}
\end{equation}
These are the source's profiles, expressed using our entropy
notation \cite{OpenAI119I,OpenAI119Reserve}.

\begin{lemma}[The two capacities are an algebraic allocation]
\label{lem:capacities}
Put
\[
\alpha=1-m^2,\qquad c_m=h(m)-\alpha\ell.
\]
Then \(c_m\ge0\), and
\begin{equation}
\mathcal B_m(I)
=
\inf_{\substack{u+v=I\\
0\le u\le c_m\\0\le v<\alpha\ell}}
\left\{2u+\alpha F(v/\alpha)\right\}.
\label{eq:capacities}
\end{equation}
The infimum is attained at \(u=\min\{I,c_m\}\).
\end{lemma}

\begin{proof}
Integrating the power series for \(\atanh r\) gives
\[
\psi(r)=\sum_{k\ge1}\frac{r^{2k}}{2k(2k-1)}.
\]
Its positive coefficients sum to \(\ell\), by continuity at
\(r=1\). Hence \(\psi(m)\le m^2\ell\), proving \(c_m\ge0\).

At fixed \(u+v=I\), increasing \(u\) cannot increase the
objective, since its derivative is
\(2-F'((I-u)/\alpha)\le0\).
The largest feasible \(u\) is \(\min\{I,c_m\}\).
Substitution gives \(2I\) when \(I\le c_m\), and
\[
2c_m+\alpha F((I-c_m)/\alpha)
\]
otherwise. These are exactly the two branches of
\eqref{eq:Bprofile}.
\end{proof}

This allocation identity is not a decomposition of a physical
channel. Proving it does not prove the source's bound
\(\Prod(g)\ge\widehat{\mathcal B}_{\E g}(\Isoft(g))\).

\subsection{Gate 2: joining, three-point support, and thinning}

For interior \(a,b\), set
\begin{equation}
c(a,b)=\frac{a-b}{4}
\bigl(\atanh a-\atanh b\bigr).
\label{eq:joiningcost}
\end{equation}
The source extends \(c\) by zero at \((1,1)\) and
\((-1,-1)\), and by \(+\infty\) at every other boundary pair.

For \(|m|+\delta<1\), \(\delta>0\), and
\[
0<e\le
\frac{h(m+\delta)+h(m-\delta)}2,
\]
its relaxed joining problem is
\begin{equation}
\mathcal K(m,\delta,e)
=
\inf
\left\{
\E c(A,B):
\E A=m+\delta,\ \E B=m-\delta,\
\frac{\E h(A)+\E h(B)}2\le e
\right\}.
\label{eq:joiningproblem}
\end{equation}
The infimum ranges over arbitrary joint laws on
\([-1,1]^2\), not just laws arising from a particular finite
cube.

The source's claimed optimizer has the support table
\[
\begin{array}{c|c|c}
\text{atom}&\text{mass}&\text{contribution}\\ \hline
(a_c,b_c)&\lambda&
\text{all nonzero entropy and joining cost}\\
(1,1)&\pi_+&0\\
(-1,-1)&\pi_-&0
\end{array}
\]
with
\[
\lambda+\pi_++\pi_-=1,\qquad
\lambda(a_c-b_c)=2\delta.
\]
The mean sum determines the remaining masses. Optimality
against \emph{every} admissible joint law, nonnegativity of the
masses, and coverage of each entropy budget are separate
obligations \cite{OpenAI119Joining}.

For common-output thinning, write
\[
x_c=\frac{a_c+b_c}{2},\quad
d_c=\frac{a_c-b_c}{2},\quad
e_c=\frac{h(a_c)+h(b_c)}2,\quad
J_c=h(x_c)-e_c.
\]
Adding \((1,1)\) with retained core mass \(\lambda\) gives
\[
x=1-\lambda+\lambda x_c,\quad
d=\lambda d_c,\quad e=\lambda e_c.
\]
If
\[
\overline h=\frac{h(x+d)+h(x-d)}2,\qquad
j=\overline h-e,\qquad J=h(x)-\overline h,
\]
the asserted payment is
\begin{equation}
F(j+J)-F(j)\le\lambda F(J_c)
\label{eq:thinning}
\end{equation}
under its stated core hypotheses
\cite{OpenAI119Thinning}.

The audit must retain the original individual child entropies
in the child profiles even though the joining relaxation
constrains only their average. A candidate three-atom law
does not establish optimizer uniqueness or budget coverage.
Moreover, a relaxed optimizer need not have the dyadic
weights of a prescribed finite cube.

A joining cost is not a decoder. The posterior table printed
later in this paper is not relabelled as the optimizer of
\eqref{eq:joiningproblem}.

\subsection{Gate 3: dimension induction and classical semigroup}

For a field \(g\), define the number operator
\[
\Num g(x)=\frac12\sum_{i=1}^n\bigl(g(x)-g(x^{(i)})\bigr),
\]
where \(x^{(i)}\) flips coordinate \(i\).
For interior \(g\), put
\[
\Prod(g)=\E[\atanh(g)\Num g].
\]

\begin{lemma}[Exact classical identities]
\label{lem:semigroup}
Let \(P_t=T_{e^{-t}}\). Then
\[
P_t=e^{-t\Num},\qquad
\frac{d}{dt}\Isoft(P_tg)=-\Prod(P_tg).
\]
If \(g_+,g_-\) are the two sections in one coordinate,
\begin{equation}
\Prod(g)
=
\frac{\Prod(g_+)+\Prod(g_-)}2
+\E c(g_+,g_-).
\label{eq:productionsplit}
\end{equation}
\end{lemma}

\begin{proof}
For \(A\subseteq\{1,\ldots,n\}\), the Walsh character
\(\chi_A(x)=\prod_{i\in A}x_i\) satisfies
\[
T_\rho\chi_A=\rho^{|A|}\chi_A,\qquad
\Num\chi_A=|A|\chi_A.
\]
These characters form a basis, proving the semigroup identity.

The mean is conserved, \(h'=-\atanh\), and
\(\partial_tP_tg=-\Num P_tg\). Differentiation of
\eqref{eq:softinfo} gives the production identity.
Separating the last-coordinate term in \(\Num\) gives
\eqref{eq:productionsplit}, with the factor \(1/4\) in
\eqref{eq:joiningcost}.
\end{proof}

\begin{proposition}[Conditional scalar-rate integration]
\label{prop:conditionalflow}
If the inequality
\[
\Prod(g)\ge F(\Isoft(g))
\]
is available for every interior field on a fixed cube, then
\eqref{eq:external-soft} follows on that cube for every soft
summary.
\end{proposition}

\begin{proof}
For an interior field, put
\(r_t=\psi^{-1}(\Isoft(P_tg))\).
Where \(r_t>0\), the chain rule and \eqref{eq:F} give
\[
r_t'
=
-\frac{\Prod(P_tg)}{\atanh r_t}
\le-r_t.
\]
Thus \(r_t\le e^{-t}r_0\).
If information becomes zero, the field is constant by
Lemma~\ref{lem:scalar} and remains so.

For boundary-valued inputs apply the result to
\((1-\eta)u\), then let \(\eta\downarrow0\) using continuity
of finite sums. Correlation zero follows by taking the
constant mean. Negative correlations follow from
\[
T_{-\rho}u(y)=T_\rho u(-y)
\]
and invariance of uniform averages under \(y\mapsto-y\).
\end{proof}

The hypothesis of Proposition~\ref{prop:conditionalflow} is
not proved in this manuscript. In particular, the exact
semigroup identity does not prove the nonlinear induction
step. The mean-dependent joining profile is intended to supply
that step \cite{OpenAI119I,ChenGohariNair}.

This semigroup acts on classical functions. No matrix-algebra
Lindblad evolution is specified.

\subsection{Gate 4: asymmetric Hellinger induction and arithmetic}

Let \(f_+,f_-\) be Boolean sections and
\(d_\pm=T_\rho f_\pm\) on the remaining cube. The exact recursion is
\begin{align}
T_\rho f(y',1)
&=\frac{1+\rho}{2}d_+(y')
+\frac{1-\rho}{2}d_-(y'),\\
T_\rho f(y',-1)
&=\frac{1-\rho}{2}d_+(y')
+\frac{1+\rho}{2}d_-(y').
\label{eq:Hrecursion}
\end{align}
The means of the sections may differ. Replacing them by a
balanced pair would change the problem.

The 119-02 route uses asymmetric profiles before reflection,
and a separately calibrated semigroup-energy continuation
\cite{OpenAI119Induction,OpenAI119II}.
For \(g_t=P_tf\), the elementary derivative underlying such
a continuation is
\begin{equation}
\frac{d}{dt}\E H(g_t)
=
\E\!\left[\frac{g_t}{H(g_t)}\Num g_t\right]
=
\frac14\sum_i
\E\!\left[
(g_t-g_t^{(i)})
\left(
\frac{g_t}{H(g_t)}
-\frac{g_t^{(i)}}{H(g_t^{(i)})}
\right)
\right],
\label{eq:Henergy}
\end{equation}
whenever the field is interior. The identity follows from
\(H'(r)=-r/H(r)\) and symmetrization under coordinate flips.
For a noised coordinate the derivative is
\(e^{-2t}/\sqrt{1-e^{-2t}}\).
An estimate must preserve that calibration to preserve
sharpness.

The source's finite arithmetic certificates concern scalar
inequalities supporting this route
\cite{OpenAI119Arithmetic}.
Their audit requires:
\begin{enumerate}
\item the complete parameter domain and every subdivision;
\item positivity of any cleared denominator;
\item nonnegative sides before squaring;
\item rigorous interval endpoints and series tails;
\item coverage of seams, singular limits, and all bias regimes;
\item the correct logical passage from the scalar estimates to
the dimension-free assertion.
\end{enumerate}
For example, nonnegative Bernstein coefficients prove the sign
of a specified polynomial on a specified box because the
Bernstein basis is nonnegative and sums to one. They do not
identify an omitted polynomial or cover an omitted box.

We do not report execution of the source's certificates.
The arithmetic in Section~\ref{sec:finite} instead belongs
to our entirely specified sixteen-function instance.

\subsection{Gate 5: Hellinger implies information}

The implication is a classical convexity statement, not an
identification of the two functionals. We prove it in
Section~\ref{sec:implication}, then apply it only to the finite
certificate proved here. It neither makes 119-02 a premise
of 119-01 nor transfers either assertion to quantum inputs.

\section{Stages 3 and 6: the complete finite certificate}
\label{sec:finite}

\subsection{The frozen instance and its entire kernel}

Fix
\begin{equation}
n=2,\qquad \rho_0=\frac12,\qquad
\varepsilon_0=\frac14,\qquad
s_0=H(\rho_0)=\frac{\sqrt3}{2},\qquad
C_0=1-s_0.
\label{eq:frozen}
\end{equation}
Order the cube as
\[
v_1=(1,1),\quad v_2=(1,-1),\quad
v_3=(-1,1),\quad v_4=(-1,-1).
\]
The complete noise matrix is
\begin{equation}
K_{\rho_0}
=
\frac1{16}
\begin{pmatrix}
9&3&3&1\\
3&9&1&3\\
3&1&9&3\\
1&3&3&9
\end{pmatrix}.
\label{eq:fourmatrix}
\end{equation}
Its row and column sums are one. The joint law of \((X,Y)\)
is \(K_{\rho_0}/4\).

For Boolean \(f\), define its Hellinger loss and its gap from
the coordinate bound by
\begin{equation}
\Loss(f)=H(\E f)-\E H(T_{\rho_0}f),
\qquad
\Gap(f)=C_0-\Loss(f).
\label{eq:lossgap}
\end{equation}
Concavity of \(H\) and mean preservation imply
\(\Loss(f)\ge0\).

\subsection{Exhaustive classification of the sixteen functions}

Input coordinate permutations, independent input sign changes,
and output complementation preserve the mean up to sign and
preserve the distribution of the noised values up to sign.
They therefore preserve both \(\Loss\) and \(\Gap\).

\begin{lemma}[Four exhaustive orbits]
\label{lem:orbits}
Every Boolean function on \(\Omega_2\) belongs to exactly one
of the following four classes:
\begin{enumerate}
\item the two constants;
\item the four signed coordinates;
\item the two signed parity functions \(\pm x_1x_2\);
\item the eight functions with one exceptional vertex, or their
complements.
\end{enumerate}
A representative of the last orbit is
\[
q(x)=1-2\,\mathbf1_{\{x=(1,1)\}}.
\]
\end{lemma}

\begin{proof}
Classify by the size of the positive set. Sizes zero and four
give the constants. Sizes one and three give eight functions,
all in the exceptional-vertex orbit.

At size two there are six unordered pairs of vertices.
Four pairs are edges of the square; their indicators give
signed coordinates. The remaining two pairs are diagonals;
they give signed parity. This accounts for
\(2+4+2+8=16\) functions.
\end{proof}

The complete representative calculation is:
\begin{center}
\small
\begin{tabular}{@{}lcrrrr@{}}
\toprule
Representative & \(m\) &
\(f(v_1)\)&\(f(v_2)\)&\(f(v_3)\)&\(f(v_4)\)\\
\midrule
\(1\)&\(1\)&\(1\)&\(1\)&\(1\)&\(1\)\\
\(x_1\)&\(0\)&\(1\)&\(1\)&\(-1\)&\(-1\)\\
\(x_1x_2\)&\(0\)&\(1\)&\(-1\)&\(-1\)&\(1\)\\
\(q\)&\(1/2\)&\(-1\)&\(1\)&\(1\)&\(1\)\\
\bottomrule
\end{tabular}

\medskip

\begin{tabular}{@{}lrrrr@{}}
\toprule
Representative &
\(T_{\rho_0}f(v_1)\)&
\(T_{\rho_0}f(v_2)\)&
\(T_{\rho_0}f(v_3)\)&
\(T_{\rho_0}f(v_4)\)\\
\midrule
\(1\)&\(1\)&\(1\)&\(1\)&\(1\)\\
\(x_1\)&\(1/2\)&\(1/2\)&\(-1/2\)&\(-1/2\)\\
\(x_1x_2\)&\(1/4\)&\(-1/4\)&\(-1/4\)&\(1/4\)\\
\(q\)&\(-1/8\)&\(5/8\)&\(5/8\)&\(7/8\)\\
\bottomrule
\end{tabular}
\end{center}

These entries follow by multiplication by
\eqref{eq:fourmatrix}; no dimension induction is being used.

For the biased representative, the full three-atom posterior
table is
\begin{equation}
\begin{array}{c|ccc}
d=T_{\rho_0}q(Y)&-1/8&5/8&7/8\\ \hline
\Prob(d)&1/4&1/2&1/4\\
\Prob(q(X)=1\mid Y)&7/16&13/16&15/16\\
H(d)&3\sqrt7/8&\sqrt{39}/8&\sqrt{15}/8
\end{array}.
\label{eq:posterior}
\end{equation}
This is a posterior law for this function, not a solution of
the unrelated joining optimization
\eqref{eq:joiningproblem}.

\subsection{Exact integer-square certificates}

\begin{lemma}[Root enclosures]
\label{lem:roots}
Let \(Q=100000\). The following strict enclosures hold:
\[
\frac{173205}{Q}<\sqrt3<\frac{173206}{Q},
\qquad
\frac{264575}{Q}<\sqrt7<\frac{264576}{Q},
\]
\[
\frac{387298}{Q}<\sqrt{15}<\frac{387299}{Q},
\qquad
\frac{624499}{Q}<\sqrt{39}<\frac{624500}{Q}.
\]
\end{lemma}

\begin{proof}
For each row of the following table, both displayed residuals
are positive integers:
\[
\begin{array}{c|r|r|r|r}
k&a&b&kQ^2-a^2&b^2-kQ^2\\ \hline
3&173205&173206&27975&318436\\
7&264575&264576&69375&459776\\
15&387298&387299&259196&515401\\
39&624499&624500&998999&250000
\end{array}.
\]
Hence \(a^2<kQ^2<b^2\). Taking nonnegative square roots and
dividing by \(Q\) proves the result.
\end{proof}

Define
\begin{equation}
B_q=
\frac{3\sqrt7+2\sqrt{39}+\sqrt{15}}{32}.
\label{eq:Bq}
\end{equation}

\begin{theorem}[Oai119-A finite Hellinger certificate]
\label{thm:finite}
For every Boolean function \(f:\Omega_2\to\{-1,1\}\), with
\(X\) uniform and independent symmetric noise of correlation
\(1/2\),
\begin{equation}
H(\E f)-\E H(T_{1/2}f)
\le
1-\frac{\sqrt3}{2}.
\label{eq:finiteH}
\end{equation}
Equality holds if and only if
\[
f\in\{x_1,-x_1,x_2,-x_2\}.
\]
The gaps are exactly
\begin{equation}
\begin{array}{c|c|c|c}
\text{class}&H(\E f)&\E H(T_{1/2}f)&\Gap(f)\\ \hline
\text{constant}&0&0&1-\sqrt3/2\\[2pt]
\text{signed coordinate}&1&\sqrt3/2&0\\[2pt]
\text{signed parity}&1&\sqrt{15}/4&
(\sqrt{15}-2\sqrt3)/4\\[2pt]
\text{exceptional vertex}&\sqrt3/2&B_q&
1+B_q-\sqrt3
\end{array}.
\label{eq:gaptable}
\end{equation}
In particular,
\begin{align}
\frac{102}{1000}
&<
\Gap(x_1x_2)
<
\frac{103}{1000},
\label{eq:paritygap}\\
\frac{27}{1000}
&<
\Gap(q)
<
\frac{28}{1000},
\label{eq:biasedgap}
\end{align}
and every function that is not a signed coordinate satisfies
\begin{equation}
\Gap(f)>\frac{27}{1000}.
\label{eq:uniformgap}
\end{equation}
\end{theorem}

\begin{proof}
The representative tables and evenness of \(H\) give every
entry in \eqref{eq:gaptable}. Lemma~\ref{lem:orbits} transfers
them to all sixteen functions.

For parity, Lemma~\ref{lem:roots} gives
\[
\frac{40886}{400000}
<
\frac{\sqrt{15}-2\sqrt3}{4}
<
\frac{40889}{400000}.
\]
These bounds lie strictly between \(102/1000\) and
\(103/1000\).

For the exceptional-vertex orbit, the same root enclosures give
\[
\frac{
3(264575)+2(624499)+387298+32Q-32(173206)
}{32Q}
<
1+B_q-\sqrt3
\]
and
\[
1+B_q-\sqrt3
<
\frac{
3(264576)+2(624500)+387299+32Q-32(173205)
}{32Q}.
\]
The two numerators are, respectively, \(87429\) and \(87467\).
Therefore
\[
\frac{87429}{3200000}
<
\Gap(q)
<
\frac{87467}{3200000}.
\]
Since
\[
86400<87429<87467<89600,
\]
this proves \eqref{eq:biasedgap}.

For constants,
\[
\Gap(f)
>
1-\frac{173206}{200000}
=
\frac{26794}{200000}
>
\frac{27}{1000}.
\]
Thus every noncoordinate class has a strictly positive gap,
and the coordinate class has gap zero. This proves the
inequality, the equality classification, and
\eqref{eq:uniformgap}.
\end{proof}

\begin{remark}[What has been evaluated]
The certificate specifies the entire input set, all admissible
Boolean functions through exhaustive orbits, every kernel
entry, every posterior value, and explicit integer comparisons.
It does not rely on a floating-point search or an unprinted
optimizer.

The general three-point joining optimizer has not been
evaluated here. That is not the selected next theorem:
the selected next theorem is the finite Hellinger certificate,
which is now proved.
\end{remark}

\section{The Courtade--Kumar implication as a corollary}
\label{sec:implication}

The conversion below is the classical implication of
Anantharam, Bogdanov, Chakrabarti, Jayram, and Nair
\cite[Proposition 1]{ABCJN}. It is reproduced with all
normalizations fixed.

\begin{lemma}[Convex entropy conversion]
\label{lem:conversion}
Define
\[
\varphi(t)=
\hbin\!\left(\frac{1-\sqrt{1-t^2}}2\right),
\qquad 0\le t\le1.
\]
Then \(\varphi\) is increasing and convex, and
\begin{equation}
\hbin\!\left(\frac{1+u}{2}\right)=\varphi(H(u))
\qquad(-1\le u\le1).
\label{eq:conversionidentity}
\end{equation}
For \(0\le a\le b\le1\),
\begin{equation}
\varphi(b)-\varphi(a)
\ge\frac{b^2-a^2}{2\ell}.
\label{eq:conversionlower}
\end{equation}
\end{lemma}

\begin{proof}
For \(0<t<1\), put \(v=\sqrt{1-t^2}\). Differentiation gives
\[
\varphi'(t)=
\frac{t}{2v\ell}\ln\frac{1+v}{1-v}\ge0,
\]
\[
\varphi''(t)=
\frac{\ln((1+v)/(1-v))-2v}{2v^3\ell}\ge0.
\]
Indeed,
\[
\ln\frac{1+v}{1-v}=2\atanh v\ge2v.
\]
Continuity extends monotonicity and convexity to the endpoints.
The same inequality gives \(\varphi'(t)\ge t/\ell\);
integration proves \eqref{eq:conversionlower}.

Finally,
\(\sqrt{1-H(u)^2}=|u|\), and binary entropy is symmetric
about \(1/2\). This proves \eqref{eq:conversionidentity}.
\end{proof}

\begin{proposition}[A pointwise Hellinger certificate implies information]
\label{prop:HtoI}
Fix one Boolean function and one symmetric-noise experiment on
a uniform cube. Write
\[
d=T_\rho f,\quad m=\E f,\quad
a=H(m),\quad b=\E H(d),\quad s=H(\rho).
\]
If
\[
a-b\le1-s,
\]
then
\[
\Info_2(f(X);Y)
\le1-\hbin\!\left(\frac{1-\rho}{2}\right).
\]
More quantitatively, if
\[
\eta=(1-s)-(a-b)\ge0,
\]
then
\begin{equation}
1-\hbin\!\left(\frac{1-\rho}{2}\right)
-\Info_2(f(X);Y)
\ge
\varphi(s+\eta)-\varphi(s).
\label{eq:quantbridge}
\end{equation}
\end{proposition}

\begin{proof}
Concavity of \(H\) gives \(0\le b\le a\le1\).
Equation~\eqref{eq:MI}, \eqref{eq:conversionidentity}, and
Jensen's inequality imply
\[
\Info_2(f(X);Y)
=
\varphi(a)-\E\varphi(H(d))
\le\varphi(a)-\varphi(b).
\]
Put \(\delta=a-b\). Convexity implies that an increment of
length \(\delta\) increases when its interval is shifted to
the right. Hence
\[
\varphi(a)-\varphi(b)
\le
\varphi(1)-\varphi(1-\delta)
=
1-\varphi(s+\eta).
\]
Here \(s+\eta=1-\delta\in[0,1]\).
Since
\[
\varphi(s)
=
\hbin\!\left(\frac{1-|\rho|}{2}\right)
=
\hbin\!\left(\frac{1-\rho}{2}\right),
\]
the assertions follow.
\end{proof}

\begin{corollary}[Complete finite Courtade--Kumar certificate]
\label{cor:finiteCK}
At \(n=2\), \(\rho=1/2\), and \(\varepsilon=1/4\),
\[
\Info_2(f(X);Y)\le1-\hbin(1/4)
\]
for every Boolean \(f\). Equality holds precisely for the four
signed coordinates. Every other Boolean function satisfies
\begin{equation}
1-\hbin(1/4)-\Info_2(f(X);Y)>\frac1{50}
\quad\text{bit}.
\label{eq:strictMI}
\end{equation}
For the named parity comparison,
\[
\Info_2(x_1x_2;Y)=1-\hbin(3/8).
\]
\end{corollary}

\begin{proof}
Apply Proposition~\ref{prop:HtoI} to
Theorem~\ref{thm:finite}. For a noncoordinate function,
\(\eta=\Gap(f)>27/1000\). By
\eqref{eq:conversionlower},
\[
\varphi(s_0+\eta)-\varphi(s_0)
\ge
\frac{2s_0\eta+\eta^2}{2\ell}
\ge\frac{s_0\eta}{\ell}.
\]
Now \(s_0>4/5\), by squaring, and
\(\ell=\int_1^2dt/t<1\). Consequently the information gap is
strictly greater than
\[
\frac45\frac{27}{1000}
=
\frac{108}{5000}
>
\frac1{50}.
\]

For a coordinate, \eqref{eq:MI} and
\(T_{1/2}x_i=x_i/2\) give the exact value
\(1-\hbin(1/4)\).
For parity, the posterior mean is \(\pm1/4\), giving
\(1-\hbin(3/8)\).
\end{proof}

This is a corollary of the finite Hellinger certificate.
No all-dimensional information theorem has been imported.

\section{Stage 2: pricing only the specified objects}
\label{sec:pricing}

\subsection{An exact classical sampler}

\begin{proposition}[A finite stochastic implementation]
\label{prop:sampler}
The joint law at the frozen instance can be generated using
six independent fair bits and deterministic classical operations.
Two bits generate \(X\) uniformly. Two further independent
pairs generate the two noise signs: flip coordinate \(i\)
exactly when both bits of its pair are one.
\end{proposition}

\begin{proof}
Each flip has probability \(1/4\), and the flip events are
independent of one another and of \(X\).
Thus the induced transition probabilities are \(9/16\),
\(3/16\), or \(1/16\), according to whether zero, one, or two
coordinates differ. This is exactly \eqref{eq:fourmatrix}.
Each of the \(64\) seeds is equiprobable, so the joint table
has denominator \(64\).
\end{proof}

This is an explicit upper resource count for one classical
sampler. It is not a minimum-memory theorem, an optimal circuit
claim, or a Choi-rank calculation.

\subsection{A complete-record statistical allowance}

\begin{specification}[Declared score and repeated experiments]
\label{spec:statistics}
Fix the truth table \(f\), the ideal kernel
\eqref{eq:fourmatrix}, and the score
\[
W_f(y)=H(T_{1/2}f(y))\in[0,1].
\]
Perform \(N\) independent attempted experiments. Every attempt
must be scored by the predeclared rule; no success-only
postselection or unaccounted stopping is allowed.

The score uses the already known ideal posterior table.
It is not an estimator of an unknown conditional entropy
from a single observed conditional label.
\end{specification}

\begin{proposition}[Finite-sample coverage for the declared score]
\label{prop:coverage}
Suppose each actual output law is within total variation \(e\)
of the specified uniform ideal law, and each recorded score
approximates \(W_f\) with deterministic error at most \(\kappa\).
For independent repetitions with the same actual law, put
\[
\widehat\Gap
=
C_0-H(\E f)+\overline W_N.
\]
Then, with probability at least \(1-\alpha\),
\begin{equation}
|\widehat\Gap-\Gap(f)|
\le
\sqrt{\frac{\ln(2/\alpha)}{2N}}+e+\kappa.
\label{eq:coverage}
\end{equation}
An additional calibration-failure probability \(\beta\)
enlarges the failure probability to at most \(\alpha+\beta\).
\end{proposition}

\begin{proof}
A function in \([0,1]\) changes in expectation by at most the
total variation distance. Score rounding changes the sample
mean by at most \(\kappa\).

For completeness, for any \(W\in[0,1]\), the log moment
generating function of \(W-\E W\) has value and derivative
zero at zero. Its second derivative is a variance under an
exponentially tilted law, at most \(1/4\). Hence
\[
\ln\E e^{t(W-\E W)}\le t^2/8.
\]
Independence, exponential Markov inequality, and optimization
over \(t\) give
\[
\Prob\{|\overline W_N-\E W|>r\}\le2e^{-2Nr^2}.
\]
Taking \(r=\sqrt{\ln(2/\alpha)/(2N)}\), then adding the
model and rounding allowances, proves \eqref{eq:coverage}.
The calibration assertion is a union bound.
This is Hoeffding's bounded-variable argument \cite{Hoeffding}.
\end{proof}

The proof discipline is comparable to Cheung's complete-record
statistical interfaces in En01-B and En01-C
\cite{CheungEn01B,CheungEn01C}. Their physical statistics are
not identified with the present score.
A confidence interval does not prove a sharp constant:
Theorem~\ref{thm:finite} is an exact calculation, while
Proposition~\ref{prop:coverage} concerns repeated sampling
under additional hypotheses.

\subsection{The comparison templates and their limits}

\begin{longtable}{@{}p{.24\linewidth}p{.34\linewidth}p{.34\linewidth}@{}}
\toprule
Template & What can be priced or compared & What is not supplied\\
\midrule
\endfirsthead
\toprule
Template & What can be priced or compared & What is not supplied\\
\midrule
\endhead
\bottomrule
\endfoot

En02-A,
\texttt{thm:Dprime} &
A specified quantum instrument's one-shot environment and
register ledger. &
Neither the classical kernel \(T_\rho\) nor
\(\Info(f(X);Y)\).\\[5pt]

En02-B,
\texttt{thm:B1} &
Correctness and live-memory accounting for a supplied finite
decoder program. &
A Boolean optimizer or a decoder from a joining law.\\[5pt]

Landmark I; VIII-B &
Destructive readout semantics and a record-only
quantum-recovery obstruction. &
Coordinate optimality. The supplied quantitative
\texttt{prop:classical-recovery} is in VIII-B, version 3.\\[5pt]

En07-A &
Complete-complement recovery and readout-and-drop. &
Hellinger contraction.
Its supplied \texttt{thm:exact} is a recovery criterion,
not the label of a cube-noise inequality.\\[5pt]

En01-B / En01-C &
Coverage for declared complete-record statistics. &
A sharp inequality for all truth tables and correlations.\\[5pt]

Em03-F,
\texttt{thm:EB} &
A particular measure-and-prepare channel and its recovery
obstruction. &
The cube-noise operator or its extremizers.\\[5pt]

Em03-G,
\texttt{thm:lower} &
A positive error lower bound at each fixed finite model
parameter. &
A vanishing-error theorem from the lower bound alone.
Growing-resource transmission is a separate result.\\[5pt]

Oai272-A context &
The nominated uniform secret-bit gap in its declared
protocol model. &
A mutual-information inequality or a verified premise
of this certificate.\\[5pt]

Oai265-A,
\texttt{thm:separation} &
Static-record, channel, and history separation. &
A Boolean function or a cube-noise theorem.\\[5pt]

Oai276 context &
Classical transmission through a specified qubit damping
channel. &
The present uniform-cube summary problem.\\[5pt]

Oai274 context &
The nominated parity/circuit-complexity comparison. &
A premise about \(T_\rho\), or a transfer of a coordinate
optimizer to QAC\(^{0}\).\\
\end{longtable}

The Cheung references in this table are scoped comparisons
drawn from the supplied passages
\cite{CheungEn02A,CheungEn02B,CheungI,CheungVIIIB,
CheungEn07A,CheungEm03F,CheungEm03G,CheungOai265A}.
Labels not supported by the supplied excerpts are not silently
promoted to verified results.

Families 272, 274, 276, and 279 remain catalogue comparisons.
No factoring theorem, zero-key construction, circuit lower
bound, or damping-capacity theorem is needed for the local
proof \cite{Dossier119,Oai276Context}.

\section{Stages 3 and 4: evaluation and hypothesis changes}
\label{sec:hypotheses}

\subsection{A sharp statement and its finite evaluation}

The external general assertions name a sharp constant and an
attaining example. The present certificate additionally prints:
\begin{enumerate}
\item all four input points and all transition probabilities;
\item an exhaustive partition of the sixteen Boolean functions;
\item every representative truth table and noised value;
\item a signed coordinate attaining equality;
\item parity and a biased noncoordinate function with exact gaps;
\item finite integer-square certificates for the numerical bounds;
\item the information implication and its normalization in bits.
\end{enumerate}

A three-atom posterior distribution is not automatically the
three-point optimizer of the local joining problem. Neither a
Lean target nor an implementation ledger supplies that missing
identification.

\subsection{Uniform input is an operative hypothesis}

\begin{example}[Dropping uniformity changes even the coordinate value]
\label{ex:nonuniform}
Let \(S\) be a uniform sign, but prepare
\[
X=(S,S)
\]
rather than a uniform point of \(\Omega_2\).
Apply independent crossover-\(1/4\) noise to both coordinates,
and take \(f(X)=X_1=S\). Then
\[
\Info_2(S;Y_1,Y_2)>\Info_2(S;Y_1)
=1-\hbin(1/4).
\]

Indeed, \(Y_2\) carries nonzero additional information about
\(S\) conditional on \(Y_1\): both conditional values of \(S\)
have positive probability, and their \(Y_2\)-laws differ.
Strict concavity of binary entropy makes the information
increase strict. Explicitly,
\[
\Info_2(S;Y_1,Y_2)
=
\frac58\bigl(1-\hbin(1/10)\bigr).
\]
The two observations disagree with probability \(3/8\),
in which case the posterior is fair; when they agree, the
posterior error is \(1/10\).

Thus the frozen universal constant cannot simply be retained
after dropping the uniform-product-input assumption.
\end{example}

For this example the posterior kernel is not
\eqref{eq:kernel}; Bayes' rule uses the changed input law.

\subsection{Independent flips are also operative}

\begin{example}[Correlated noise preserves parity perfectly]
\label{ex:correlated}
Keep \(X\) uniform on \(\Omega_2\), but let the two noise signs
be one common sign:
\[
Z_1=Z_2=Z,\qquad \E Z=\frac12.
\]
Each coordinate separately still has crossover \(1/4\), but
the flips are not independent. Then
\[
Y_1Y_2=X_1X_2Z^2=X_1X_2.
\]
Consequently parity has mutual information one bit with \(Y\),
and its posterior mean has absolute value one.
Its Hellinger loss is therefore one, not at most
\(1-\sqrt3/2\).
\end{example}

Marginal crossover probabilities do not specify the product
noise model.

\subsection{Soft summaries, output bias, and asymmetric noise}

For a soft \(u\), the conditional entropy \(\E h(u)\) need not
vanish. Replacing \(\Isoft(u)\) by \(h(\E u)\) would erase that
randomization cost and change the fixed-information problem.

Arbitrary output bias means that \(m=\E f\) is unrestricted
while \(X\) remains uniform. It does not mean that the input
distribution is arbitrary.

Asymmetric bit transitions generally destroy the symmetry
\(K(x,y)=K(y,x)\), uniform stationarity, and the one-parameter
Walsh multiplier \(\rho^{|A|}\). Such a model requires a new
posterior kernel and a new comparison theorem.

\subsection{Parity and circuit complexity}

For a Walsh character of degree \(k\),
\[
T_\rho\chi_A=\rho^k\chi_A,\qquad |A|=k.
\]
Thus parity is degree two in our finite example and degree
\(n\) on the full \(n\)-variable parity family.
This is a spectral calculation, not a circuit lower bound.

A QAC\(^{0}\) parity obstruction concerns allowed gates,
depth, size, and possibly ancillary systems. None of those
parameters occurs in Theorem~\ref{thm:finite}.
Conversely, no nominated circuit-complexity theorem proves
the Hellinger inequality.

\subsection{A classical kernel does not specify a quantum extension}

Here is an explicit non-identification, used only as a
comparison. For a qubit let
\[
\Delta(A)=\kb00A\kb00+\kb11A\kb11,
\]
and
\[
\mathcal B_\varepsilon(A)
=
(1-\varepsilon)A+\varepsilon XAX,
\]
where \(X\) is the Pauli bit flip.
The two CPTP maps
\(\mathcal B_\varepsilon\) and
\(\mathcal B_\varepsilon\circ\Delta\) agree on every diagonal
input. They therefore implement the same classical binary
symmetric transition on computational-basis data.

Nevertheless,
\[
\mathcal B_\varepsilon(\proj+)=\proj+,
\qquad
(\mathcal B_\varepsilon\circ\Delta)(\proj+)=I_2/2.
\]
The output trace distance is \(1/2\).
The second extension is measure-and-prepare; the classical
transition table alone did not select that extension.

This is the kind of distinction between records and full
quantum outputs emphasized by Cheung's readout and residual
comparisons \cite{CheungVIIIA,CheungVIIIB,CheungEn07A}.
The standard measure-and-prepare characterization is given
in \cite{HSR}.

Similarly, \(H(t)\) is a classical affinity:
for the two Bernoulli laws
\[
p_t=\left(\frac{1+t}{2},\frac{1-t}{2}\right),
\qquad
p_{-t}=\left(\frac{1-t}{2},\frac{1+t}{2}\right),
\]
one has
\[
\sum_j\sqrt{p_t(j)p_{-t}(j)}=H(t).
\]
The fact that classical affinities admit diagonal-matrix
representations does not prove an inequality for arbitrary
noncommuting density operators, entangled inputs, or collective
POVMs.

\subsection{Quantities that remain separate}

\begin{longtable}{@{}p{.29\linewidth}p{.63\linewidth}@{}}
\toprule
Proposed change & Exact boundary\\
\midrule
\endfirsthead
\toprule
Proposed change & Exact boundary\\
\midrule
\endhead
\bottomrule
\endfoot
Hellinger loss to mutual information &
Requires the convexity argument in
Section~\ref{sec:implication}; the functionals are not equal.\\[4pt]
Classical summary to quantum recovery &
Requires a quantum input/output interface and a recovery
criterion. A coordinate optimizer is not a quantum decoder.\\[4pt]
One-bit information to channel capacity &
Requires a coding model and asymptotic error criterion.
The summary problem is not a capacity optimization.\\[4pt]
Information to secret key &
Requires an adversarial system, access specification,
and secrecy criterion. No such system is present here.\\[4pt]
Finite exact certificate to general inequality &
Requires all dimensions and all correlations. A finite
arithmetic instance does not supply these quantifiers.\\[4pt]
Sampling coverage to a sharp constant &
Requires an exact mathematical upper bound; a confidence
statement is not that bound.\\[4pt]
Area-law record to cube contraction &
Requires a specified mathematical interface. None is supplied
by similarly named entropy quantities.\\
\end{longtable}

\section{Stage 5: gravitational and recovery readings remain separations}
\label{sec:separations}

The mathematical data here are a finite set, its uniform law,
a stochastic matrix, and a Boolean truth table. They specify
neither a metric nor a gravitational interaction.

The parameter \(t\) in \(P_t=T_{e^{-t}}\) is a classical
Markov-semigroup parameter. Calling it time does not identify
it with a spacetime coordinate or an evaporation process.
The number operator \(\Num\) acts on functions on the cube;
no physical Lindblad generator is specified. This does not
deny that a classical Markov process can be embedded in a
larger matrix evolution. Such an embedding is additional data,
as the preceding quantum-extension example illustrates.

A Page curve requires a specified time-indexed radiation state
and access partition. An island or horizon requires geometric
and dynamical structure. A gravity-generated-entanglement test
requires a preparation, mediator model, output state, and
comparison class. None occurs in the contraction experiment.

Cheung's Oai265-A separates static entropy records from recovery
and radiation histories, and the supplied XIV-I/J passages
separate defined internal kernels from an unconstructed full
characteristic composition
\cite{CheungOai265A,CheungXIVI,CheungXIVJ}.
Those are relevant cautions about transferring premises,
not analytic inputs to our finite cube calculation.

Enter, where invoked in the comparison manuscripts, remains
destructive readout. A classical record does not become a
reference-preserving unknown-state decoder because it contains
a particularly informative bit
\cite{CheungI,CheungVIIIB,CheungEn07A}.

No Page curve, island, horizon, Hawking-radiation derivation,
gravity-generated entanglement, exclusion of classical gravity,
or spacetime-emergence theorem is established.

\section{Release: the completed plan and unchanged general claims}
\label{sec:release}

\begin{center}
\small
\begin{tabularx}{\linewidth}{@{}p{.08\linewidth}X
p{.31\linewidth}@{}}
\toprule
Stage & Completed task & Status\\
\midrule
0 &
Uniform input, independent symmetric noise, the two profiles,
information units, external statements, and formalization
scope are distinguished. &
Frozen; no external general theorem is a premise.\\[5pt]
1 &
Scalar, joining, semigroup, asymmetric Hellinger, arithmetic,
and implication interfaces are audited. &
Elementary identities proved; universal proof obligations
remain explicit.\\[5pt]
2 &
A concrete sampler and finite-sample allowance are supplied.
Comparison ledgers retain their own interfaces. &
No decoder or resource optimum is inferred from a template.\\[5pt]
3 &
The exact kernel, posterior tables, equality example, and
strict numerical gaps are printed. &
Evaluation supplied for the frozen instance.\\[5pt]
4 &
Input law, independence, summary type, functional,
coding task, and quantum interface are varied separately. &
No silent hypothesis weakening.\\[5pt]
5 &
Thermal, gravitational, temporal, and recovery readings are
kept separate. &
No standing physical problem is solved.\\[5pt]
6 &
The one selected finite Hellinger theorem is proved, with the
Courtade--Kumar conclusion as a corollary. &
Completed by Theorem~\ref{thm:finite} and
Corollary~\ref{cor:finiteCK}.\\
\bottomrule
\end{tabularx}
\end{center}

The exact mathematical conclusion is
\[
\boxed{
\begin{gathered}
n=2,\qquad \rho=\frac12,\qquad
H(\E f)-\E H(T_{1/2}f)\le1-\frac{\sqrt3}{2},\\[2pt]
\text{equality exactly for }\pm x_1,\ \pm x_2,\\[2pt]
\Gap(f)>\frac{27}{1000}
\quad\text{for every other Boolean function},\\[2pt]
\frac{102}{1000}<\Gap(x_1x_2)<\frac{103}{1000},\\[2pt]
\Info_2(f(X);Y)\le1-\hbin(1/4),\\[2pt]
\text{information gap}>\frac1{50}\text{ bit
for every nonsigned-coordinate function}.
\end{gathered}}
\]

The finite certificate now exists. The following conclusions
still do not follow:
\begin{itemize}
\item independent verification of 119-01 or 119-02;
\item a completed proof of the inspected Lean targets;
\item formalization of 119-02's \texttt{thm:main} by targets
that name 119-01;
\item a noncommutative fidelity inequality, a quantum
mutual-information inequality, or a collective-measurement
optimizer;
\item a Page curve or a gravity test.
\end{itemize}

These are logical scope boundaries. They do not assert that
other researchers cannot prove a broader statement independently,
or that no proof exists elsewhere.

\appendix

\section{Optional exact-arithmetic checker}
\label{app:checker}

The following optional Python code independently reconstructs
the kernel and inspects all sixteen truth tables. It uses
rational arithmetic and integer square roots only.
It is not needed as a premise of the printed proof.
No execution is asserted.

\begingroup
\small
\begin{verbatim}
from fractions import Fraction as F
from itertools import product
from math import isqrt

vertices = [(1,1), (1,-1), (-1,1), (-1,-1)]
rho = F(1,2)
Q = 100000

def kernel(x, y):
    out = F(1)
    for xi, yi in zip(x, y):
        out *= (1 + rho*xi*yi)/2
    return out

K = [[kernel(x,y) for y in vertices] for x in vertices]
expected = [
    [9,3,3,1],
    [3,9,1,3],
    [3,1,9,3],
    [1,3,3,9]
]
assert K == [[F(a,16) for a in row] for row in expected]
assert all(sum(row, F(0)) == 1 for row in K)
assert all(sum(K[i][j] for i in range(4)) == 1
           for j in range(4))

def noise(f):
    return tuple(
        sum((K[y][x]*f[x] for x in range(4)), F(0))
        for y in range(4)
    )

def sqrt_interval(z):
    assert z >= 0
    A = z.numerator * Q*Q
    B = z.denominator
    a = isqrt(A // B)
    assert a*a*B <= A < (a+1)*(a+1)*B
    return F(a,Q), F(a+1,Q)

def H_interval(t):
    return sqrt_interval(1-t*t)

coord = set()
for i in range(2):
    for sign in (-1,1):
        coord.add(tuple(sign*x[i] for x in vertices))

assert len(coord) == 4
assert noise((1,1,-1,-1)) == (
    F(1,2),F(1,2),-F(1,2),-F(1,2)
)
assert noise((1,-1,-1,1)) == (
    F(1,4),-F(1,4),-F(1,4),F(1,4)
)
assert noise((-1,1,1,1)) == (
    -F(1,8),F(5,8),F(5,8),F(7,8)
)

slo, shi = H_interval(rho)
counts = {"constant":0, "coordinate":0,
          "parity":0, "exceptional":0}

for f in product((-1,1), repeat=4):
    m = F(sum(f),4)
    d = noise(f)

    if f in coord:
        counts["coordinate"] += 1
        assert m == 0
        assert all(abs(v) == rho for v in d)
        continue

    if abs(m) == 1:
        counts["constant"] += 1
    elif m == 0:
        counts["parity"] += 1
    else:
        counts["exceptional"] += 1

    hlo, hhi = H_interval(m)
    intervals = [H_interval(v) for v in d]
    blo = sum((a for a,b in intervals), F(0))/4
    bhi = sum((b for a,b in intervals), F(0))/4

    gap_lower = (1-shi)-hhi+blo
    gap_upper = (1-slo)-hlo+bhi

    assert gap_lower > F(27,1000)
    if m == 0:
        assert gap_lower > F(102,1000)
        assert gap_upper < F(103,1000)
    if abs(m) == F(1,2):
        assert gap_upper < F(28,1000)

assert counts == {
    "constant":2, "coordinate":4,
    "parity":2, "exceptional":8
}

root_rows = [
    (3,173205,173206,27975,318436),
    (7,264575,264576,69375,459776),
    (15,387298,387299,259196,515401),
    (39,624499,624500,998999,250000)
]
for k,a,b,left,right in root_rows:
    assert k*Q*Q-a*a == left > 0
    assert b*b-k*Q*Q == right > 0
\end{verbatim}
\endgroup

The integer-root routine is sound because
\[
a^2\le\left\lfloor Q^2z\right\rfloor<(a+1)^2
\]
implies
\(a/Q\le\sqrt z<(a+1)/Q\).
The checker covers a finite list of sixteen objects. It makes
no assertion about all dimensions.

\section{Documentary corrections}
\label{app:documentary}

\begin{enumerate}
\item The notation \(H\) in 119-01 denotes sign entropy, whereas
\(H\) in 119-02 denotes \(\sqrt{1-t^2}\).
This manuscript uses \(h\) for the former throughout.
\item The supplied En07-A \texttt{thm:exact} is a
complete-complement recovery criterion. Readout-and-drop
is a separate statement in its interface.
\item The supplied Landmark I excerpt proves a finite
Born/destructive-readout characterization. The explicit
quantitative \texttt{prop:classical-recovery} excerpt
appears in VIII-B, version 3.
\item Em03-G's supplied \texttt{thm:lower} gives a strictly
positive lower bound at each fixed finite coupling.
The compatibility of such bounds with growing-resource
transmission is not itself an upper-bound construction.
\item The large XIV--XV--XVI dossier concerns different domains,
equation spaces, and distributions. Its characteristic-map
and admission obligations are not steps in the proof of the
finite cube certificate.
\end{enumerate}

\section*{Declarations}
\addcontentsline{toc}{section}{Declarations}

\paragraph{Authorship and identifier.}
The requested identifier Oai119-A is used for this development.
It does not attribute authorship to N.~Cheung or assert
registration or endorsement by another series.

\paragraph{Mathematical scope.}
The principal result is the printed exact certificate for
\(n=2,\rho=1/2\), together with its classical information
corollary. Supporting scalar and probabilistic results are
proved locally. The universal Family 119 assertions are not
verified or assumed.

\paragraph{Sources.}
External manuscript assertions are identified as such.
Cheung's supplied manuscripts are cited for their stated
comparison interfaces, not imported as proofs of contraction.
No exhaustive corpus scan is claimed.

\paragraph{Formal and computational status.}
No successful Lean execution, execution of the appendix,
independent numerical run, successful pdfLaTeX build,
referee approval, or journal acceptance is asserted.
An unexecuted program is not substituted for the printed
integer-square proof.

\paragraph{Unchanged standing boundaries.}
For the distinct programmes described in the supplied dossier,
this manuscript establishes no result changing their status:
\[
\boxed{
\text{O.1 remains }\NOTCLOSED,\qquad
\text{the downstream XV-B admission exit is not opened},\qquad
\text{XVI-N is not discharged}.
}
\]
This does not deny the existence of technical continuation
manuscripts or their separately scoped interface theorems.
No inherited quantum coefficient is admitted here.

\begin{thebibliography}{99}
\addcontentsline{toc}{section}{References}

\bibitem{CourtadeKumar2014}
T.~A.~Courtade and G.~R.~Kumar.
Which Boolean functions maximize mutual information on noisy inputs?
\emph{IEEE Transactions on Information Theory}
\textbf{60}(8) (2014), 4515--4525.
doi:10.1109/TIT.2014.2326877.
Historical formulation of the conjecture, not an assertion of
its present verification status.
\url{https://people.eecs.berkeley.edu/~courtade/pdfs/CourtadeKumar_TransITAug2014.pdf}

\bibitem{ABCJN}
V.~Anantharam, A.~Bogdanov, A.~Chakrabarti, T.~S.~Jayram,
and C.~Nair.
\emph{A conjecture regarding optimality of the dictator function
under Hellinger distance}.
Manuscript presented at the Information Theory and Applications
Workshop, February 2017.
Relevant items: Lemma 1 and Proposition 1, the classical
Hellinger-to-information implication.
\url{https://chandra.ie.cuhk.edu.hk/pub/papers/HC/hel-conj.pdf}

\bibitem{ODonnell}
R.~O'Donnell.
\emph{Analysis of Boolean Functions}.
Cambridge University Press, 2014.
Revised author text, 2021.
Uniform-cube Fourier and noise-operator conventions.
\url{https://arxiv.org/abs/2105.10386}

\bibitem{ChenGohariNair}
Z.~Chen, A.~Gohari, and C.~Nair.
\emph{A differential equation approach to the most-informative
Boolean function conjecture}.
2025 IEEE International Symposium on Information Theory.
Extended manuscript: arXiv:2502.10019.
Cited for the local-production and semigroup methodology;
no unverified auxiliary inequality is imported.
\url{https://arxiv.org/abs/2502.10019}

\bibitem{OpenAI119I}
OpenAI.
\emph{Sharp binary-information contraction on the discrete cube}.
Family 119-01 manuscript, dated 24 September 2026.
Relevant source labels:
\texttt{main:soft}, \texttt{main:ck},
and \texttt{upgrade:production}.
Recorded as external claims in this manuscript.
\url{https://github.com/openai/math/blob/main/preprints/Sharp-binary-information-contraction-on-the-discrete-cube-September-24-2026/build/main.tex}

\bibitem{OpenAI119Joining}
OpenAI.
\emph{A joining cost with one entropy budget}.
Section \texttt{canonical.tex} of Family 119-01.
Relevant labels:
\texttt{canonical:priced} and
\texttt{canonical:coverage}.
\url{https://github.com/openai/math/blob/main/preprints/Sharp-binary-information-contraction-on-the-discrete-cube-September-24-2026/build/sections/canonical.tex}

\bibitem{OpenAI119Reserve}
OpenAI.
\emph{A reserve that survives adding either common output}.
Section \texttt{reserve.tex} of Family 119-01.
The two-capacity allocation and mean-dependent reserve.
\url{https://github.com/openai/math/blob/main/preprints/Sharp-binary-information-contraction-on-the-discrete-cube-September-24-2026/build/sections/reserve.tex}

\bibitem{OpenAI119Thinning}
OpenAI.
\emph{Paying the information increment by thinning}.
Section \texttt{thinning.tex} of Family 119-01.
Relevant label: \texttt{thinning:payment}.
\url{https://github.com/openai/math/blob/main/preprints/Sharp-binary-information-contraction-on-the-discrete-cube-September-24-2026/build/sections/thinning.tex}

\bibitem{OpenAI119II}
OpenAI.
\emph{Hellinger contraction with arbitrary Boolean output bias}.
Family 119-02 manuscript, dated 24 September 2026.
Relevant source label: \texttt{thm:main}.
The all-dimensional assertion is not independently verified here.
\url{https://github.com/openai/math/blob/main/preprints/Hellinger-contraction-with-arbitrary-Boolean-output-bias-September-24-2026/build/main.tex}

\bibitem{OpenAI119Induction}
OpenAI.
\emph{Dimension induction}.
Section \texttt{induction.tex} of Family 119-02.
Asymmetric-profile and section-comparison proof interface.
\url{https://github.com/openai/math/blob/main/preprints/Hellinger-contraction-with-arbitrary-Boolean-output-bias-September-24-2026/build/sections/induction.tex}

\bibitem{OpenAI119Arithmetic}
OpenAI.
\emph{Exact arithmetic conventions}.
Section \texttt{arithmetic.tex} of Family 119-02.
Bernstein, rational-interval, and integer-root certificate
conventions; no execution is reported here.
\url{https://github.com/openai/math/blob/main/preprints/Hellinger-contraction-with-arbitrary-Boolean-output-bias-September-24-2026/build/sections/arithmetic.tex}

\bibitem{OpenAI119Implication}
OpenAI.
\emph{Completion of the proof}.
Section \texttt{conclusion.tex} of Family 119-02.
Relevant label: \texttt{cor:ck}.
Reproduction of the classical implication of
Anantharam et al.; not a premise proving the general
Hellinger bound.
\url{https://github.com/openai/math/blob/main/preprints/Hellinger-contraction-with-arbitrary-Boolean-output-bias-September-24-2026/build/sections/conclusion.tex}

\bibitem{Lean119Scope}
OpenAI.
\emph{The Courtade--Kumar and Hellinger conjectures:
Lean scope note}.
Repository file \texttt{lean/docs/119.md},
consulted 14 October 2026.
The listed accompanying paper is Family 119-01.
\url{https://github.com/openai/math/blob/main/lean/docs/119.md}

\bibitem{Lean119CK}
OpenAI.
\emph{CourtadeKumar.lean}.
Repository file
\texttt{lean/ComparatorChallenges/CourtadeKumar.lean},
consulted 14 October 2026.
The inspected principal theorem body contains \texttt{sorry}.
\url{https://github.com/openai/math/blob/main/lean/ComparatorChallenges/CourtadeKumar.lean}

\bibitem{Lean119Soft}
OpenAI.
\emph{SoftChannel204.lean}.
Repository file
\texttt{lean/ComparatorChallenges/SoftChannel204.lean},
consulted 14 October 2026.
The inspected \texttt{fullMain} body contains \texttt{sorry}.
\url{https://github.com/openai/math/blob/main/lean/ComparatorChallenges/SoftChannel204.lean}

\bibitem{Hoeffding}
W.~Hoeffding.
Probability inequalities for sums of bounded random variables.
\emph{Journal of the American Statistical Association}
\textbf{58}(301) (1963), 13--30.
doi:10.1080/01621459.1963.10500830.

\bibitem{HSR}
M.~Horodecki, P.~W.~Shor, and M.~B.~Ruskai.
Entanglement breaking channels.
\emph{Reviews in Mathematical Physics}
\textbf{15} (2003), 629--641.
doi:10.1142/S0129055X03001709.
Preprint title: \emph{General Entanglement Breaking Channels}.
Cited only for the quantum-extension comparison.
\url{https://arxiv.org/abs/quant-ph/0302031}

\bibitem{CheungI}
N.~Cheung.
\emph{Landmark I}, version 2.
Supplied manuscript \texttt{I.tex}.
Relevant supplied label: \texttt{thm:main}.
Finite Born probabilities and destructive projective residuals
within the stated strategy class.
Enter Calculus Companion.

\bibitem{CheungVIIIA}
N.~Cheung.
\emph{Landmark VIII-A}, version 3.
Supplied manuscript \texttt{VIII-A-v3.tex}.
Relevant supplied label: \texttt{A:thm:residual}.
Record agreement and complete residual agreement are different
interfaces.
Enter Calculus Companion.

\bibitem{CheungVIIIB}
N.~Cheung.
\emph{Landmark VIII-B}, version 3.
Supplied manuscript \texttt{VIII-B-v3.tex}.
Relevant supplied label:
\texttt{prop:classical-recovery}.
Sharp record-only quantum-recovery obstruction.
Enter Calculus Companion.

\bibitem{CheungEn02A}
N.~Cheung.
\emph{En02-A}, version 1.
Supplied manuscript \texttt{En02-A-v1.tex}.
Relevant supplied label: \texttt{thm:Dprime}.
One-shot environment accounting and its separation from
adaptive occupancy.
Enter Calculus Companion.

\bibitem{CheungEn02B}
N.~Cheung.
\emph{En02-B}, version 1.
Supplied manuscript \texttt{En02-B-v1.tex}.
Relevant supplied label: \texttt{thm:B1}.
Resource-certified finite decoder soundness.
Enter Calculus Companion.

\bibitem{CheungEn07A}
N.~Cheung.
\emph{En07-A}, version 1.
Supplied manuscript \texttt{En07-A.tex}.
Relevant supplied label: \texttt{thm:exact}.
Complete-complement recovery; separately described
readout-and-drop conventions.
Enter Calculus Companion.

\bibitem{CheungEn01B}
N.~Cheung.
\emph{En01-B}, version 2.
Supplied manuscript \texttt{En01-B-v2.tex}.
The supplied dossier records \texttt{thm:bounded}
for bounded complete-record statistics.
No physical diagnostic is identified with the present
Hellinger score.
Enter Calculus Companion.

\bibitem{CheungEn01C}
N.~Cheung.
\emph{En01-C}, version 1.
Supplied manuscript \texttt{En01-C.tex}.
The supplied dossier records \texttt{thm:certificate}
for clipping, complete attempted-run records, calibration,
and finite-sample coverage.
Enter Calculus Companion.

\bibitem{CheungEm03F}
N.~Cheung.
\emph{Em03-F}, version 1.
Supplied manuscript \texttt{Em03-F-v1.tex}.
Relevant supplied labels:
\texttt{thm:EB} and \texttt{thm:recovery}.
A specified measure-and-prepare packet channel,
not the cube-noise operator.
Enter Calculus Companion.

\bibitem{CheungEm03G}
N.~Cheung.
\emph{Em03-G}, version 1.
Supplied manuscript \texttt{Em03-G-v1.tex}.
Relevant supplied labels:
\texttt{thm:lower},
\texttt{thm:compacttransmission}, and
\texttt{prop:Fobstruction}.
Finite-coupling lower bounds and growing-resource transmission
are distinguished.
Enter Calculus Companion.

\bibitem{CheungOai265A}
N.~Cheung.
\emph{Oai265-A}, supplied version 1.
Relevant supplied label: \texttt{thm:separation}.
Static records, recovery, and radiation histories are distinct.
Enter Calculus Companion.

\bibitem{CheungXIVI}
N.~Cheung.
\emph{Landmark XIV-I}, version 1.
Supplied manuscript \texttt{XIV-I.tex}.
Relevant supplied labels:
\texttt{thm:I2}, \texttt{thm:I3}, and \texttt{thm:release}.
The internal amplitude construction and unresolved joint
characteristic map are separate objects.
Documentary comparison only.
Enter Calculus Companion.

\bibitem{CheungXIVJ}
N.~Cheung.
\emph{Landmark XIV-J}, version 1.
Supplied manuscript \texttt{XIV-J.tex}.
Relevant supplied labels:
\texttt{thm:J2}, \texttt{thm:release},
and \texttt{cor:noadmission}.
Supported-sector reference, unresolved complete map, and
no quantum admission in the stated release.
Documentary comparison only.
Enter Calculus Companion.

\bibitem{Oai276Context}
\emph{Oai276-A: A finite certificate for a generalized
amplitude-damping Holevo optimum}.
Earlier development supplied in this conversation.
Cited only to distinguish a damping-channel information
problem from the discrete-cube problem.
No attribution to N.~Cheung or independent verification of
its external all-block-length claims is asserted.

\bibitem{Dossier119}
\emph{User-supplied Oai119-A plan and comparative source dossier}.
Includes version-specific Cheung excerpts and catalogue
comparisons for Families 119, 265, 272, 274, 276, and 279.
Supplied retrieval identifier:
\texttt{178f233f (retrieval-3)}.
Not an exhaustive corpus inspection, formal verification,
or transfer of model-specific premises.

\end{thebibliography}

\end{document}