Manuscript Em02-D@4 · Em02-D-v4.tex · proposition · fcf2fac7
Proposition: Integrated-vertex asymptotics
Integrated-vertex jets and the known six rows › Second and third temporal derivatives · lines 1285–1393 · proof included or linked
Em02-D@4#prop:vertex-jets, Em02-D@4#eq:M-leading, Em02-D@4#eq:DM-bound, Em02-D@4#eq:D2M, Em02-D@4#eq:D3M, Em02-D@4#eq:fourth-time, Em02-D@4#eq:mixed-fourth
On the compact outer null cone,
For the uses below, the remainders and their direct scale derivatives are controlled by . The estimate remains valid after two derivatives.
In particular, has no inverse-quartic term.
Proof. The first three statements follow from Lemma lem:master. Total differentiation splits into propagation and weight differentiation. The only inverse-cubic terms in are
They give . Parity removes the nominal second-order master coefficient, so .
For , use Theorem thm:first-correction. At zero,
Thus, for frozen weights,
For a spatial propagation derivative, define
In layer coordinates, at fixed unscaled time,
Therefore
For frozen ,
Summing (eq:fourth-time) and (eq:mixed-fourth) with weights gives
The kinetic vertex contributes minus one half of this.
When one of the three total time derivatives falls on the weight, the coefficient is . Terms with two or three weight derivatives are lower order. The mass vertex contributes at inverse-cubic order. These are exactly (eq:P3).
The first-correction estimate uses fourteen weight derivatives; the output derivative raises this to fifteen. Allowing two incidence spectators gives seventeen. The remaining leading-master operations require no more: the interior estimates below use at most eleven. Repeating the calculation with gives the scale-leading coefficients and , and the same remainder bounds.
Displayed formulas in this passage
Em02-D@4#eq:M-leading · line 1288
Em02-D@4#eq:DM-bound · line 1288
Em02-D@4#eq:D2M · line 1288
Em02-D@4#eq:D3M · line 1288
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Em02-D@4#eq:fourth-time · line 1331
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Em02-D@4#eq:mixed-fourth · line 1352
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