Manuscript En10-A@1 · En10-A.tex · theorem · 0a1d7743
Theorem: Finite Enter instrument
The finite Enter theorem and estimation contract · lines 616–919 · proof included or linked
En10-A@1#thm:main, En10-A@1#eq:probabilities, En10-A@1#eq:bernoulli, En10-A@1#eq:tail, En10-A@1#eq:radius, En10-A@1#eq:coverage, En10-A@1#eq:shots, En10-A@1#eq:FA, En10-A@1#eq:FC, En10-A@1#eq:FI-ledger
Freeze the interface of Section sec:interface, adopt Born semantics and Definition def:names, and impose Assumption ass:statistics for the estimation statements. Then the following hold.
Complete instrument identity. The instrument is a complete CP instrument with classical output. For every finite untouched retained factor , including an arbitrary reference,
on all input operators. Discarding its record leaves the unconditional -marginal unchanged.
Consumption and residual scope. Both measured data names are consumed. The newly returned object is the classical word ; no quantum - or -output belongs to the instrument. A conditional spectator or inaccessible implementation complement is not a return of those names.
Declared likelihood. The one-shot probabilities are
In particular, are independent Bernoulli variables with
Separate finite-shot inference. The estimator (eq:estimator) is the maximum-likelihood estimator for the coarsened Bernoulli data . It is not asserted to be the maximum-likelihood estimator for the complete four-outcome record.
For every ,
For , define
Uniformly over ,
Thus a sufficient shot budget for a radius at most is
Fisher-information ledger. For , the achieved one-shot information in the coarsened data is
The complete word has information
They satisfy
The last bound also applies to any POVM on the post-step data state . Independent repetition multiplies the respective Fisher informations by .
The output interpretation is finite-model estimate under declared access. The theorem supplies neither a quantum-return decoder nor a physical identification with Galactic transport.
Proof. We prove each claim on the declared interface.
and consumption. Lemma lem:identity proves the complete identity and its reference extensions. Equivalently, the -branch on a record-only interface has Kraus rows
Their completeness is
Lemma lem:consumption proves the name statement.
. The squared moduli of both and are the transition matrix
The diagonal gate changes phases but not computational populations.
Conditional on source component , the normal output has probabilities . The antiqubit's probability of value , after relaxation, is . Conditional on source component , the normal output has probabilities , and the antiqubit's probability of value is .
The diagonal output populations conditional on either source component factor accordingly. This remains true despite coherences in the quantum state: amplitude damping transfers diagonal populations as stated, and its off-diagonal matrix elements do not contribute to these computational probabilities. Mixing the two source components gives (eq:probabilities). Summing the outcomes with gives
The product preparation and product device assumptions give independence.
maximization. For a count , the Bernoulli likelihood is proportional to
Its unconstrained maximizing value is ; restricting it to the interval gives the projection of onto . Applying the affine inverse gives (eq:estimator), including endpoint counts.
. For completeness, let be Bernoulli with mean , and set
Then , and is the variance of a Bernoulli variable under an exponentially tilted law. Hence , and integration yields
Independence and exponential Markov bounds therefore give
This is the Bernoulli instance of Hoeffding's inequality Hoeffding1963.
Projection onto cannot increase distance from . Consequently,
Taking proves (eq:tail). Taking , and using , proves (eq:radius)–(eq:coverage). Equation (eq:shots) follows directly.
Fisher information. For a Bernoulli law with derivative ,
Differentiating (eq:probabilities) gives
which proves (eq:FC). All four probabilities are strictly positive under the calibration assumptions.
comparisons. Let denote the hidden source component, with . Its score is
Thus
For any outcome obtained through a -independent conditional law given , the outcome score equals
Conditional Jensen gives
This applies to the complete word . It also applies to any POVM on : its probabilities are
which have exactly the required mixture form.
Finally, is a deterministic coarsening of . Its score is the conditional expectation of the complete-word score given . A second application of conditional Jensen gives .
For independent repetitions, scores add and have mean zero, so the squared-score expectations add. This proves the -shot information statements and completes the proof.
Displayed formulas in this passage
En10-A@1#eq:probabilities · line 647
En10-A@1#eq:bernoulli · line 667
En10-A@1#eq:tail · line 681
En10-A@1#eq:radius · line 688
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En10-A@1#eq:shots · line 703
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