Manuscript I-B-VP@3 · I-B-VP-v3.tex · theorem · 93c04eb4
Theorem: Complete product positivity ledger
Spectrum, positivity, and scale · lines 1651–1718 · proof included or linked
I-B-VP@3#thm:spectrum
For :
The negative transverse eigenvalues are satisfying
Their number, with multiplicity, is the number of negative eigenvalues of . There are no transverse zero eigenfunctions. Thus the full product operator is nonnegative exactly when .
In a full finite chart, rotation invariance is equivalent to diagonality of . Rotation by sends to . On boundary charts the corresponding condition is invariance of the whole relation.
If the deficient orders are distinct, the dilation-invariant relations are exactly the coordinate choices of Friedrichs or . If and , there is in addition
This is on and Friedrichs on .
For , every has one transverse eigenvalue . Friedrichs is the only nonnegative massless extension in the untwisted product class.
Proof. A negative transverse eigenfunction is a linear combination of . Its boundary condition is precisely the displayed determinant condition, by the calculation in Theorem thm:krein.
The compressed matrix increases strictly in Loewner order from zero to infinity. The ordered eigenvalues of its sum with therefore increase strictly and continuously from the eigenvalues of to positive infinity. Exactly its initially negative eigenvalues cross zero, counted with multiplicity. The resolvent difference has finite rank, so the transverse essential spectrum remains . Zero-energy radial solutions , or , cannot be square integrable at infinity.
Rotations multiply each boundary component by . For two deficient modes their charge difference is one, giving the stated transformation.
Modulo a common scalar normalization, dilations act by , . With distinct positive orders all weights are distinct, so an invariant Lagrangian is a coordinate sum containing exactly one of each paired axes. At equal orders an invariant Lagrangian is in the weight spaces. The intermediate one-dimensional choices give .
Finally matches at .
Displayed formulas in this passage
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