Manuscript II-B@1 · II-B-v1.tex · theorem · bfd2eb3c

Theorem: Certificate preservation under a surjective dictionary

Pullback of the complete finite certificate › Deterministic label pullback · lines 1580–1616 · proof included or linked

II-B@1#thm:pullback, II-B@1#eq:pullback-left

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If is surjective, then

and

The complete left kernel is

Every such annihilator also annihilates .

Proof. A surjective dictionary makes injective: each original coordinate is read by at least one code. Hence it preserves the ranks and the right kernel.

The original pivot columns become times the indicator vectors of the and fibers. Their annihilator equations are precisely (eq:pullback-left). They span the complete image, so the equations are sufficient. The target has coefficient on those two indicator vectors and is therefore annihilated by the same rows.

Displayed formulas in this passage

  • II-B@1#eq:pullback-left · line 1592

  • unlabeled · line 1583

  • unlabeled · line 1588

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