Manuscript II@2 · II.tex · lemma · 50d64def

Lemma: Inverse on conserved currents

Locked kinematics, action, and contacts › Quadratic action and conserved-current inverse · lines 435–461 · proof included or linked

II@2#lem:inverse

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If and , then

Also .

Proof. Write . For ,

Substitution in the Fourier transform of (eq:K0) cancels the terms and the remaining trace terms, leaving . Direct substitution of (eq:gauge-tensor) proves the second identity.

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