Remark: Endpoint equality is not zero-cue equality

The condition $B_{1,c}(c_{\mathrm{v}}-c_{\mathrm{a}})=0$ makes the two endpoint representations equal, but need not make them equal to the zero-cue representation. The stronger condition $B_{1,c}=0$ eliminates all first-layer cue dependence. Downstream cancellation can also eliminate functional cue influence without eliminating cue weights.