Manuscript VI@1 · VI.tex · proposition · b5b60afb

Proposition: When a finite fit is global

Finite-renormalization spaces and certificate requirements › Finite membership and separation · lines 2253–2276 · proof included or linked

VI@1#prop:injective-evaluation

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Let

If evaluation on is injective on , then implies on .

There exists some injective evaluation family of size at most , but this existence statement supplies neither explicit smearings nor rational evaluations.

Proof. The difference belongs to and vanishes on . Injectivity makes it zero.

For existence, start with no evaluation rows. If the common evaluation kernel in is nonzero, select a nonzero function in that kernel and a label where it is nonzero. Adding that row strictly decreases the kernel dimension. At most steps give zero kernel.

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