Manuscript VI@1 · VI.tex · proposition · b5b60afb
Proposition: When a finite fit is global
Finite-renormalization spaces and certificate requirements › Finite membership and separation · lines 2253–2276 · proof included or linked
VI@1#prop:injective-evaluation
Let
If evaluation on is injective on , then implies on .
There exists some injective evaluation family of size at most , but this existence statement supplies neither explicit smearings nor rational evaluations.
Proof. The difference belongs to and vanishes on . Injectivity makes it zero.
For existence, start with no evaluation rows. If the common evaluation kernel in is nonzero, select a nonzero function in that kernel and a label where it is nonzero. Adding that row strictly decreases the kernel dimension. At most steps give zero kernel.
Displayed formulas in this passage
unlabeled · line 2256