Manuscript VI@1 · VI.tex · proposition · b5b60afb

Proposition: Algebraic observable quotient

The linearized interface and a sourced nonempty domain › What linearization at the chosen background gives · lines 629–662 · proof included or linked

VI@1#prop:linear-quotient, VI@1#eq:linear-quotient

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The quotient

is well defined. Its elements induce gauge-invariant linear functionals on free solutions.

Proof. The linearized Bianchi identity implies , so the denominator is contained in the numerator. The free Hessian is formally self-adjoint: it is the second variation of the quadratic action, and its explicit expression also verifies this by integration by parts. Consequently, a test in the denominator pairs to zero with every solution of .

A numerator test annihilates every smooth pure gauge:

All integrations by parts are justified by compactness of the tests.

Displayed formulas in this passage

  • VI@1#eq:linear-quotient · line 632

  • unlabeled · line 656

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