Manuscript VIII-ST@1 · VIII-ST.tex · section · fe979f3b

The five-command word

Guarded flow and a complete five-command history › The five-command word · lines 1598–1634

VIII-ST@1#eq:fiveword

For $q = 6$ , $T_{6} = {- 1, 0, 1}$ . Start at $m = 0, s = - 1$ , incoming mode, source stage zero, and $ν_{G} = ν_{S} = 1$ . Supply $m_{src} = 1$ , for example with

z_{+} = 6 arctan (1/64), ρ_{+} = \frac{1}{2} (I + z_{+} Z) .

The chronological word is

W = G_{- 1 \to - 1/2}; S_{tab}; G_{- 1/2 \to 0^{-}}; E_{3 \to 6}; G_{0^{+} \to 1/2} .

\toprule k \midrule 0 12345 \bottomrule command initial G S_{tab} G E_{3 \to 6} G s - 1 - 1/2 - 1/2 0^{-} 0^{+} 1/2 m 001111 (ν_{G}, ν_{S}) (1, 1) (1, 1) (1, 0) (1, 0) (0, 0) (0, 0) τ_{P} in the selected description - 1 - 1/2 - 1/2 001

Displayed formulas in this passage

VIII-ST@1#eq:fiveword · line 1609
$W = G_{- 1 \to - 1/2}; S_{tab}; G_{- 1/2 \to 0^{-}}; E_{3 \to 6}; G_{0^{+} \to 1/2} .$
unlabeled · line 1604
$z_{+} = 6 arctan (1/64), ρ_{+} = \frac{1}{2} (I + z_{+} Z) .$
unlabeled · line 1619
$\toprule k \midrule 0 12345 \bottomrule command initial G S_{tab} G E_{3 \to 6} G s - 1 - 1/2 - 1/2 0^{-} 0^{+} 1/2 m 001111 (ν_{G}, ν_{S}) (1, 1) (1, 1) (1, 0) (1, 0) (0, 0) (0, 0) τ_{P} in the selected description - 1 - 1/2 - 1/2 001$

The five-command word

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