Manuscript XI-D@1 · XI-D.tex · section · 994a5c1b

Why a complete observable is a different problem

A necessary free-order closure condition › Why a complete observable is a different problem · lines 849–875

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Let . For a complete candidate beginning , the first closure coefficient could involve both

Theorem thm:conditional does not exclude such a cancellation. The production sheet's equation for alone has no leading term on which that correction can act.

There is a further Cauchy-data distinction. For a compact plateau parameter , X-A's preflight gives . A proposed scalar co-transformation proportional to can then participate in a complete observable's coefficient cancellation.

The free witness above is not such a plateau parameter. Its response is , not , because the coordinate data are frozen while the free ghost has nonzero initial time derivative. X-A never asserted covariance for those ghost data. Thus neither its classical theorem nor ghost number bookkeeping proves the requested bare closure.

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