Manuscript XIII-C@1 · XIII-C.tex · section · e6556893

XIII-B's release, copied

C0: copied release and the selected problem › XIII-B's release, copied · lines 312–339

XIII-C@1#eq:tree-input, XIII-C@1#eq:tree-branches-input, XIII-C@1#eq:R-convention

The constructed tree datum is not recomputed:

V_{g} \in F_{mc, pol}, R_{1}^{(0)} = - ⟨ O^{'}, G_{act}^{R} V_{g}^{'} ⟩ \in F_{mc, pol}, Q_{H} R_{1}^{(0)} \in E_{H},

R_{1}^{(0)} = ⟨ O^{'}_{γ}, r_{g} [ϕ] ⟩ + ⟨ O^{'}_{ϕ}, p_{1} [γ; ϕ] ⟩ .

The selected convention remains

R_{1} (V_{g}; O) = \frac{i}{ℏ} (T_{2}^{ren} (V_{g}, O) - V_{g} ⋆_{H} O) .

Its ordered values are zero when the entire interaction support is later, and $(i /ℏ) [O, V_{g}]_{⋆_{H}}$ when the entire observable support is later. The literal equality with $V_{g} ⋆_{H} O$ is closed and is not reopened.

Displayed formulas in this passage

XIII-C@1#eq:tree-input · line 315
$V_{g} \in F_{mc, pol}, R_{1}^{(0)} = - ⟨ O^{'}, G_{act}^{R} V_{g}^{'} ⟩ \in F_{mc, pol}, Q_{H} R_{1}^{(0)} \in E_{H},$
XIII-C@1#eq:tree-branches-input · line 321
$R_{1}^{(0)} = ⟨ O^{'}_{γ}, r_{g} [ϕ] ⟩ + ⟨ O^{'}_{ϕ}, p_{1} [γ; ϕ] ⟩ .$
XIII-C@1#eq:R-convention · line 328
$R_{1} (V_{g}; O) = \frac{i}{ℏ} (T_{2}^{ren} (V_{g}, O) - V_{g} ⋆_{H} O) .$

Nearby in this section

input: Input statement: Binary handoff