Manuscript XIX-E@1 · XIX-E.tex · proposition · 702f146e
Proposition: Exactly consistent subdivisions with different limits
Operational support does not determine spacetime or evolution › A finite channel does not select its continuous-time completion · lines 881–918 · proof included or linked
XIX-E@1#prop:continuum
One finite qubit channel admits two exactly coarse-consistent subdivision families with different continuous-time limits. Each family is complete and reference stable.
Proof. Take the common coarse channel to be , and let
Both are continuous channel groups with . At tick duration , put
Then exactly.
The bound
and expansion of the difference of two unitary conjugations imply
It holds with arbitrary references and uniformly in .
At , the first limit fixes , whereas the second sends it to . The corresponding output states are orthogonal. The limiting evolutions differ.
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