Manuscript XIX-E@1 · XIX-E.tex · proposition · 702f146e

Proposition: Exactly consistent subdivisions with different limits

Operational support does not determine spacetime or evolution › A finite channel does not select its continuous-time completion · lines 881–918 · proof included or linked

XIX-E@1#prop:continuum

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One finite qubit channel admits two exactly coarse-consistent subdivision families with different continuous-time limits. Each family is complete and reference stable.

Proof. Take the common coarse channel to be , and let

Both are continuous channel groups with . At tick duration , put

Then exactly.

The bound

and expansion of the difference of two unitary conjugations imply

It holds with arbitrary references and uniformly in .

At , the first limit fixes , whereas the second sends it to . The corresponding output states are orthogonal. The limiting evolutions differ.

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