Manuscript XV-C@1 · XV-C.tex · theorem · 5afd124d

Theorem: Exact extension criterion

An exact local distributional extension test · lines 838–905 · proof included or linked

XV-C@1#thm:extension, XV-C@1#eq:extensionbound

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Let be relatively closed and . The following are equivalent:

  1. There exists with

  2. For every compact , there are an integer and a constant such that

    for every with .

When extensions exist, their differences are exactly the distributions in supported in .

Proof. Suppose (i) holds. Distributional continuity on tests supported in a fixed compact gives a finite-order estimate

On the tests in (ii), the pairing with is the pairing with . This proves necessity.

Assume (ii). Choose a relatively compact open set and a compact containing . On the linear subspace , the functional defined by is bounded by .

The real or complex Hahn–Banach theorem extends this functional to a linear functional on satisfying the same bound. Since is continuous on every fixed-compact test space, is a distribution on . It agrees with on .

Take a locally finite cover of by such relatively compact open sets and a smooth partition of unity subordinate to it. Choose the extensions above and define

For each compactly supported test, only finitely many terms contribute. On each fixed compact test space this is a finite sum of continuous functionals, hence a distribution.

If is supported in , every term is the pairing of with . The partition of unity gives

This proves sufficiency.

Finally, two extensions have zero difference after restriction to , which is equivalent to support in . Conversely, adding a distribution supported in changes no such restriction.

Displayed formulas in this passage

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