Manuscript XVI-B@1 · XVI-B.tex · section · 6a0abffd

Spatial traceless channel

The pure-trace source calculation › Spatial traceless channel · lines 887–898

XVI-B@1#eq:h

Let

h_{ij} = n_{i} n_{j} - \frac{1}{3} δ_{ij}, n_{i} = δ_{ij} n^{j} .

This is a Euclidean spatial tensor, not Lorentzian lowering of the spatial components of $k_{a}$ .

Displayed formulas in this passage

XVI-B@1#eq:h · line 890
$h_{ij} = n_{i} n_{j} - \frac{1}{3} δ_{ij}, n_{i} = δ_{ij} n^{j} .$