Manuscript XVI-K@1 · XVI-K.tex · lemma · aa7553bb
Lemma: Explicit derivative defects
A coherent extension map on the finite span › Contact defects of differentiation · lines 1366–1441 · proof included or linked
XVI-K@1#lem:defect, XVI-K@1#eq:defect1, XVI-K@1#eq:defect2
Define
It is supported at zero and has the form
Similarly,
is supported at zero, and
No nonzero or zero value of these coefficients is asserted.
Proof. The two terms defining each defect agree off zero by (eq:Leibniz1) or (eq:Leibniz2). The defects are therefore point-supported. Differentiation raises scaling degree by at most one BF (Lemma 5.1), so their bounds are five and six. Only derivatives of of orders at most one and two, respectively, can occur.
For the first defect, its product-extension term has zero moments on . Distributional differentiation gives
On the other hand,
Thus
which proves (eq:defect1). The same sign calculation on the order-two Taylor complement proves (eq:defect2).
Displayed formulas in this passage
XVI-K@1#eq:defect1 · line 1376
XVI-K@1#eq:defect2 · line 1396
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