Manuscript XVI-K@1 · XVI-K.tex · lemma · aa7553bb

Lemma: Explicit derivative defects

A coherent extension map on the finite span › Contact defects of differentiation · lines 1366–1441 · proof included or linked

XVI-K@1#lem:defect, XVI-K@1#eq:defect1, XVI-K@1#eq:defect2

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Define

It is supported at zero and has the form

Similarly,

is supported at zero, and

No nonzero or zero value of these coefficients is asserted.

Proof. The two terms defining each defect agree off zero by (eq:Leibniz1) or (eq:Leibniz2). The defects are therefore point-supported. Differentiation raises scaling degree by at most one BF (Lemma 5.1), so their bounds are five and six. Only derivatives of of orders at most one and two, respectively, can occur.

For the first defect, its product-extension term has zero moments on . Distributional differentiation gives

On the other hand,

Thus

which proves (eq:defect1). The same sign calculation on the order-two Taylor complement proves (eq:defect2).

Displayed formulas in this passage

  • XVI-K@1#eq:defect1 · line 1376

  • XVI-K@1#eq:defect2 · line 1396

  • unlabeled · line 1369

  • unlabeled · line 1388

  • unlabeled · line 1422

  • unlabeled · line 1428

  • unlabeled · line 1433

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