Proposition: Proposition 5, master square through order κ

In the linear-antifield truncation,

Here $B_{\nu }=N_{0,\nu }(Z)=-w{Q}_{\nu }(Ah)+{\mathfrak{R}}_{{\sigma }_{\epsilon },\nu }$ is the metric-ramp piece, and $B_{g,\nu }$ is the switched-scalar breaking retained in the prepared square. The scalar variations cancel between the metric and scalar sectors. The value ${\sigma }_{\epsilon }=1$ removes $V_{\sigma }$ but not $B_g$.