Row h h c

Channels: (A) ${\Gamma }_{hhh}$ (G01+G02+G08+G14+G15) with one leg replaced by $s_{0}h(c)$; (B) own ${\Gamma }_{hh}$ pole (graviton, ghost and scalar loops) with one leg $s_{1}h=\frac{1}{2}{L}_{c}h$; (C) $\delta S_{EH,3}/\delta h\cdot {\Gamma }_{Kc}$; (D) $\delta S_2/\delta h$ (EH + gauge fixing) $\cdot {\Gamma }_{Khc}$; (E) $s\bar{c}={\sigma }_{F}F(h)$: $F\cdot {\Gamma }_{\bar{c}ch}$ (the channel missing from the Q04 ledger, erratum Q06-E2). The tree row $(S,S)/2{|}_{hhc}$ closes exactly with ${\sigma }_F=i$ and requires channel E. The scalar loops G14, G15 and the scalar part of ${\Gamma }_{hh}$ were recomputed with the Q05 engine; the matter sector alone closes exactly (incl.\ evanescent terms). Result: the 4D part of the row vanishes identically with all channels at $+1$ (the unconstrained fit has the unique solution all-equal), every single-channel deletion and a flip of ${\sigma }_F$ re-open it; an explicit evanescent remainder (248 terms, every term containing a $\tilde{g}$ contraction) is left.