Manuscript XX-A@1 · XX-A.tex · theorem · 3a586110

Theorem: Complete classical original-rod lapse

Complete raw and relational lapse through second order › The complete inverse relational map · lines 688–746 · proof included or linked

XX-A@1#thm:lapse, XX-A@1#eq:n1, XX-A@1#eq:n2, XX-A@1#eq:n1-explicit

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The frozen relational lapse has the expansion

where

All terms are supplied by (eq:clock-coeff)–(eq:Y2) and (eq:W0)–(eq:N2). The second spatial rod is constructed but does not enter .

For this background,

Proof. Composition with a formal inverse gives

The background depends only on time. Substitution of (eq:alpha1)–(eq:alpha2) gives

which is (eq:n2). The coefficient , containing , multiplies .

Since , , and ,

Equations (eq:N1), (eq:time-inverse), and give (eq:n1-explicit).

Displayed formulas in this passage

  • XX-A@1#eq:n1 · line 695

  • XX-A@1#eq:n2 · line 695

  • XX-A@1#eq:n1-explicit · line 709

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